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- >12.Equation involving roots. (Auxiliary variable)
- x-2*P∞^≤±x±-3=0
- MYSZEK 2xy
- EXAMPLE
- e
- t101
- p10
- t0
- zr
- t1
- p5
- t0
- v500
- zrm
- k@
- t2
- p3
- t0
- cxm
- k-m
- c2m
- k*m
- k@
- p1
- k@m
- cxm
- spm
- k-m
- c3m
- k=m
- c0m
- ke
- t3
- p6
- t0
- kem
- p10
- oxm
-
- slm2
- k?
- t23
- p6
- t0
- k?m
- p10
- oxm
- ka
- t4
- p6
- t0
- kam
- cqm
- kn
- t5
- p10
- t0
- knm
- k@m
- cxm
- kS
- t6
- p5
- t0
- sdm
- slm5
- kxm
- cqm
- shm
- kxm
- cqm
- k^m
- c2m
- sdm
- ke
- t7
- p3
- t0
- kem
- p10
- oxm
-
- kS
- t8
- p5
- t0
- shm
- n(m
- spm
- k+m
- c1m
- n)m
- ssm
- spm4
- ssm
- n(m
- spm3
- n)m
- ke
- t9
- p3
- t0
- kem
- p10
- oxm
-
- kS
- t10
- p5
- t0
- shm
- kxm
- spm
- k=m
- k-m
- kxm
- spm
- ;llm
- com
- crm
- kxm2
- spm
- k=m
- kxm
- spm
- ssm
- sem
- ssm
- kxm
- kS
- t17
- p3
- t0
- sgm
- spm
- ssm
- slm
- ssm
- kcm
- sdm
- slm2
- kbm
- kvm
- shm
- kxm
- kvm
- sgm
- shm
- ssm
- sem
- ssm
- kxm
- sdm
- ke
- t9
- p3
- t0
- kem
- p10
- oxm
-
- kS
- t18
- p4
- t0
- shm
- ssm
- spm5
- ssm
- kxm
- sem
- kb
- t19
- p3
- t0
- kbm
- c9m
- shm
- spm
- kb
- t20
- p3
- t0
- kbm
- kb
- kbm
- ;ke
- ;t9
- ;p2
- ;t0
- ;kem
- ;p10
- ;oxm
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- kV
- t21
- p2
- t0
- kVm
- p10
- oxm
-
- t22
- p3
- t0
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- ze
- t102
- p10
- t0
- zxm
- zem
-
- e
- q
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- BLURB
- 1`We are going to solve the equation:
- 1`#@x-2*P∞^≤±x±-3=0@.
- 2`#We open the &Equations& window and write the problem.
- 2`#To create a root we press &Shift&+&2& keys or the on-screen button.
- 3`As usual after formulating the problem we press &ENTER&.
- 23`We ask the program for a hint at the equality sign.
- 4`#In a new line
- 4`#(press &Alt&+&Insert& or the on-screen button)
- 4`#we introduce an auxiliary variable.
- 5`#To let the program know that this is just an auxiliary
- 5`#variable we use the substitution symbol "$¨"$
- 5`#(press &Ctrl&+&=& or the on-screen button).
- 5`#When we subsequently use a predefined variable again,
- 5`#we use the equality sign "$="$.
- 6`We substitute the new variable into the equation.
- 7`We press &ENTER& to check our solution.
- 8`We notice that:
- 8`#@q^2±-2q-3=(q+1)(q-3)@.
- 9`We press &ENTER& again.
- 10`#Our equation has two solutions,
- 10`#we write them using the connective OR.
- 17`We go back to the old variables.
- 18`The first solution is a contradiction and we remove it.
- 19`We raise both sides to the power "$2"$.
- 20`#To remove the root sign
- 20`#we press the &Backspace& button twice.
- 21`#This is the final result.
- 21`#We press the &Answer& button.
- ;21`#We press "&ENTER&"
- ;21`#&without making any changes& in the expression.
- 22`Now the problem is solved.
-
- 101`#We show how to use 2xy.
- 101``#"The presentation proceeds automatically."
- 101``#To move yellow panels use the mouse.
- 101`#Press ENTER on the KEYBOARD to continue.
-
- 102`#In a moment the &Examples& window will appear.
- 102`You can watch the same presentation again, or
- 102`#load the next example, or
- 102`#close the window and solve your own problem.
-